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Re: Math Question #1 [message #358036 is a reply to message #358033] Tue, 11 November 2008 04:08 Go to previous message
archerman is currently offline  archerman
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Registered: May 2007
Location: Istanbul / Turkey
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nopol10 wrote on Tue, 11 November 2008 11:38

Actually, lim(5/x,x,0) (Limit of 5/x as x -> 0) is not infinity as limit of 5/x as x->0 from the negative side and the limit of 5/x as x->0 from the positive side are not equal. Therefore the limit is undefined. It is infinity only when x->0 from the positive side and negative infinity when x->0 from the negative side.


you are right. the graph of y=5/x is similar to y=1/x which is like:

index.php?t=getfile&id=7997&private=0

so limit doesn't exist.

index.php?t=getfile&id=7998&private=0
  • Attachment: 1overx.gif
    (Size: 2.26KB, Downloaded 979 times)
  • Attachment: solution.JPG
    (Size: 13.50KB, Downloaded 779 times)


sorry for my English

http://img7.imageshack.us/img7/117/userbar730595.gif

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