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Geometry question regarding X/Y coordinates [message #152932] Wed, 04 May 2005 17:56 Go to next message
spreegem is currently offline  spreegem
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Ok. . . I have two sets of X/Y points. . . Lets say 2,4 and 5,9 I need to find the distance between the two points, what is the equation to do that? Thanks in advance. I know I learned this earlier in the year in my Geometry class but I can't find my notes about it. Laughing

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Geometry question regarding X/Y coordinates [message #152940] Wed, 04 May 2005 18:25 Go to previous messageGo to next message
Sir Phoenixx is currently offline  Sir Phoenixx
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The distance would be the square root of (x2-x1)^2 + (y2-y1)^2.

Which in this case would be: The square root of (5-2)^2 + (9-4)^2, or 5.83.

(5-2 is 3, to the second power is 9. 9-4 is 5, to the second power is 25. 9 + 25 is 34, and the square root of 34 is 5.83 (rounded).)

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Geometry question regarding X/Y coordinates [message #152945] Wed, 04 May 2005 19:04 Go to previous messageGo to next message
spreegem is currently offline  spreegem
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Ok, thanks this will help me a bunch with my MMOG. . .

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Geometry question regarding X/Y coordinates [message #152970] Wed, 04 May 2005 23:25 Go to previous messageGo to next message
Crimson is currently offline  Crimson
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The Pythagorean Theorem. Know it, love it.

I'm the bawss.

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Geometry question regarding X/Y coordinates [message #152974] Thu, 05 May 2005 00:19 Go to previous messageGo to next message
Oblivion165 is currently offline  Oblivion165
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Geometry question regarding X/Y coordinates [message #152999] Thu, 05 May 2005 06:15 Go to previous messageGo to next message
cheesesoda is currently offline  cheesesoda
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Geometry sucked. This was the first math class that I almost failed. Granted, my Geometry teacher sucked, so that did help.

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Geometry question regarding X/Y coordinates [message #153004] Thu, 05 May 2005 06:52 Go to previous messageGo to next message
flyingfox is currently offline  flyingfox
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I thought it was the pythagoras theorem (yes I know the guy's name was pythagoras)

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Geometry question regarding X/Y coordinates [message #153007] Thu, 05 May 2005 06:59 Go to previous messageGo to next message
cheesesoda is currently offline  cheesesoda
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Nope, it's Pythagorean.

Edit: I bet both would be correct, though.

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Geometry question regarding X/Y coordinates [message #153033] Thu, 05 May 2005 12:03 Go to previous messageGo to next message
snipesimo is currently offline  snipesimo
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You are wrong Crimson, that is actually the Distance Formula Razz

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Geometry question regarding X/Y coordinates [message #153035] Thu, 05 May 2005 12:12 Go to previous messageGo to next message
spreegem is currently offline  spreegem
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I get what Crimson means. . . Find out how far horizontally and vertically I need to go, then find the diagonal. A^2 + B^2 = C^2

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Geometry question regarding X/Y coordinates [message #153037] Thu, 05 May 2005 12:37 Go to previous messageGo to next message
mrpirate is currently offline  mrpirate
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snipesimo

You are wrong Crimson, that is actually the Distance Formula Razz


It's still the Pythagorean Theorem.

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Geometry question regarding X/Y coordinates [message #153060] Thu, 05 May 2005 14:16 Go to previous messageGo to next message
Dan
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What about working out the distance between:

(3,5,9)
and
(-2,3,3)

Easy Razz

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Geometry question regarding X/Y coordinates [message #153089] Thu, 05 May 2005 15:57 Go to previous messageGo to next message
ghostSWT
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Dan

What about working out the distance between:
(3,5,9)
and
(-2,3,3)Easy Razz
Um... Distance = sqrt( (P2.x - P1.x)^2 + (P2.y - P1.y)^2 + (P2.z - P1.z)^2 )

about 8.06225....

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Geometry question regarding X/Y coordinates [message #153111] Thu, 05 May 2005 18:39 Go to previous messageGo to next message
stealthkiller is currently offline  stealthkiller
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I've seen this equation in every math. Granted, distance formula is for coordinates and Pythagorean theorem is for triangles, they're basically the same thing. You'll learn to love this equation

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Geometry question regarding X/Y coordinates [message #153118] Thu, 05 May 2005 19:22 Go to previous messageGo to next message
glyde51 is currently offline  glyde51
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Nice to know I'm advanced in math...

If you need any explaining help, e-mail me. I'll do my best to help you out.

Oh, Spree, by the way, I'm going to excessivley spam Eclipse forums for a while, Wink

No. Seriously. No.

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Geometry question regarding X/Y coordinates [message #153130] Thu, 05 May 2005 21:23 Go to previous messageGo to next message
hunteroo2 is currently offline  hunteroo2
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math just goes down hill after geometry...alg2 is such a waste of time :rolleyes:

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Geometry question regarding X/Y coordinates [message #153134] Thu, 05 May 2005 21:55 Go to previous messageGo to next message
mrpirate is currently offline  mrpirate
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No way. Triple integrals are leet.

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Geometry question regarding X/Y coordinates [message #153135] Thu, 05 May 2005 22:07 Go to previous messageGo to next message
Hydra is currently offline  Hydra
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AYE DEECLAIR AN GRAMAR WAREZ!!!!!!!

spreegem

find the diagonal.

Hypotenuse.

And it's Pythagorean Theorem. Razz

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Geometry question regarding X/Y coordinates [message #153169] Fri, 06 May 2005 06:40 Go to previous messageGo to next message
Dan
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ghostSWT

Dan

What about working out the distance between:
(3,5,9)
and
(-2,3,3)Easy Razz
Um... Distance = sqrt( (P2.x - P1.x)^2 + (P2.y - P1.y)^2 + (P2.z - P1.z)^2 )

about 8.06225....


You win the prize \(^o^)/

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Geometry question regarding X/Y coordinates [message #153170] Fri, 06 May 2005 07:50 Go to previous messageGo to next message
Crimson is currently offline  Crimson
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stealthkiller

I've seen this equation in every math. Granted, distance formula is for coordinates and Pythagorean theorem is for triangles, they're basically the same thing. You'll learn to love this equation


They aren't "basically" the same thing. They ARE the same thing.

I'm the bawss.

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Geometry question regarding X/Y coordinates [message #153184] Fri, 06 May 2005 10:07 Go to previous messageGo to next message
Dan
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What about the perimeter of this triangle:

A (4,6,Cool
B (2,9,6)
C (7,3,6)

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Geometry question regarding X/Y coordinates [message #153186] Fri, 06 May 2005 10:50 Go to previous messageGo to next message
PhrozenUnit is currently offline  PhrozenUnit
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132 units

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Geometry question regarding X/Y coordinates [message #153593] Sun, 08 May 2005 17:19 Go to previous messageGo to next message
ESFEAR1 is currently offline  ESFEAR1
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something like this i think,Pythagorean Theorem a 2 + b 2 = c 2 , where c is the length of the hypotenuse and a and b are the lengths of the legs =)

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Geometry question regarding X/Y coordinates [message #153630] Sun, 08 May 2005 20:42 Go to previous message
DarkDemin is currently offline  DarkDemin
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I failed my third quarter of Geometry hurray for me!

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